What are the solutions to the equation 9(3+4x)^2=25 ?

The solutions to the equation 9(3+4x)^2=25 are x=-1/3 ,x=-7/6

Find the zeros of 9(3+4x)^2=25

The zeros of 9(3+4x)^2=25 are x=-1/3 ,x=-7/6

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9 (3 + 4 x)^{2} = 25

x = - \frac{1}{3}, x = - \frac{7}{6}

Solution steps

9 (3 + 4 x)^{2} = 25

Divide both sides by

9

(3 + 4 x)^{2} = \frac{25}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 + 4 x = \frac{25}{9} : x = - \frac{1}{3}

Solve

3 + 4 x = - \frac{25}{9} : x = - \frac{7}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{7}{6}

x^{2} - 30 x + 81 = 0

(x + 7)^{2} = (2 x - 1)^{2}

x^{2} - \frac{5}{3} x

x^{2} = 12 (x - 5)

ab c x^{2} - (a^{2} b^{2} + c^{2}) x + ab c = 0

What are the solutions to the equation 9(3+4x)^2=25 ?
The solutions to the equation 9(3+4x)^2=25 are x=-1/3 ,x=-7/6
Find the zeros of 9(3+4x)^2=25
The zeros of 9(3+4x)^2=25 are x=-1/3 ,x=-7/6