What are the solutions to the equation x^2-30x+81=0 ?

The solutions to the equation x^2-30x+81=0 are x=27,x=3

Find the zeros of x^2-30x+81=0

The zeros of x^2-30x+81=0 are x=27,x=3

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x^{2} - 30 x + 81 = 0

x = 27, x = 3

Solution steps

x^{2} - 30 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

(- 30)^{2} - 4 \cdot 1 \cdot 81 = 24

x_{1, 2} = \frac{- ( - 30 ) \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 24}{2 \cdot 1}, x_{2} = \frac{- ( - 30 ) - 24}{2 \cdot 1}

x = \frac{- ( - 30 ) + 24}{2 \cdot 1} : 27

x = \frac{- ( - 30 ) - 24}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 27, x = 3

(x + 7)^{2} = (2 x - 1)^{2}

x^{2} - \frac{5}{3} x

x^{2} = 12 (x - 5)

ab c x^{2} - (a^{2} b^{2} + c^{2}) x + ab c = 0

- 22 - 3 x^{2} - 2 x = - 3

What are the solutions to the equation x^2-30x+81=0 ?
The solutions to the equation x^2-30x+81=0 are x=27,x=3
Find the zeros of x^2-30x+81=0
The zeros of x^2-30x+81=0 are x=27,x=3