What are the solutions to the equation x^2-34=16x ?

The solutions to the equation x^2-34=16x are x=8+7sqrt(2),x=8-7sqrt(2)

Find the zeros of x^2-34=16x

The zeros of x^2-34=16x are x=8+7sqrt(2),x=8-7sqrt(2)

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x^{2} - 34 = 16 x

x = 8 + 72, x = 8 - 72

Solution steps

x^{2} - 34 = 16 x

Move

16 x

to the left side

x^{2} - 34 - 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 16 x - 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 34 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 34) = 142

x_{1, 2} = \frac{- ( - 16 ) \pm 14 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 14 2}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 14 2}{2 \cdot 1}

x = \frac{- ( - 16 ) + 14 2}{2 \cdot 1} : 8 + 72

x = \frac{- ( - 16 ) - 14 2}{2 \cdot 1} : 8 - 72

The solutions to the quadratic equation are:

x = 8 + 72, x = 8 - 72

9 x^{2} - 24 = 1

- 2 (x - 4)^{2} = - 5

6 x^{2} - 10 x - 4 = 0

4 x^{2} - 30 x + 56 = 0

x^{2} + 5 x + 2

What are the solutions to the equation x^2-34=16x ?
The solutions to the equation x^2-34=16x are x=8+7sqrt(2),x=8-7sqrt(2)
Find the zeros of x^2-34=16x
The zeros of x^2-34=16x are x=8+7sqrt(2),x=8-7sqrt(2)