What are the solutions to the equation -2(x-4)^2=-5 ?

The solutions to the equation -2(x-4)^2=-5 are x=sqrt(5/2)+4,x=-sqrt(5/2)+4

Find the zeros of -2(x-4)^2=-5

The zeros of -2(x-4)^2=-5 are x=sqrt(5/2)+4,x=-sqrt(5/2)+4

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- 2 (x - 4)^{2} = - 5

x = \frac{5}{2} + 4, x = - \frac{5}{2} + 4

Solution steps

- 2 (x - 4)^{2} = - 5

Divide both sides by

- 2

(x - 4)^{2} = \frac{5}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = \frac{5}{2} : x = \frac{5}{2} + 4

Solve

x - 4 = - \frac{5}{2} : x = - \frac{5}{2} + 4

The solutions to the quadratic equation are:

x = \frac{5}{2} + 4, x = - \frac{5}{2} + 4

6 x^{2} - 10 x - 4 = 0

4 x^{2} - 30 x + 56 = 0

x^{2} + 5 x + 2

x, 7 x^{2} - 112 x + 2 y^{2} + 448 = 0

18 x^{2} - 9 x = 0

What are the solutions to the equation -2(x-4)^2=-5 ?
The solutions to the equation -2(x-4)^2=-5 are x=sqrt(5/2)+4,x=-sqrt(5/2)+4
Find the zeros of -2(x-4)^2=-5
The zeros of -2(x-4)^2=-5 are x=sqrt(5/2)+4,x=-sqrt(5/2)+4