What are the solutions to the equation 18x^2-9x=0 ?

The solutions to the equation 18x^2-9x=0 are x= 1/2 ,x=0

Find the zeros of 18x^2-9x=0

The zeros of 18x^2-9x=0 are x= 1/2 ,x=0

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18 x^{2} - 9 x = 0

x = \frac{1}{2}, x = 0

Solution steps

18 x^{2} - 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 18 \cdot 0}{2 \cdot 18}

(- 9)^{2} - 4 \cdot 18 \cdot 0 = 9

x_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 18}, x_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 18}

x = \frac{- ( - 9 ) + 9}{2 \cdot 18} : \frac{1}{2}

x = \frac{- ( - 9 ) - 9}{2 \cdot 18} : 0

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 0

(x - 5)^{2} = - 1

6 x^{2} + 14 x + 4 = 0

x^{2} + 14 x = - 32

a, a^{2} - b^{2} = 0

2 m^{2} - 3 = 0

What are the solutions to the equation 18x^2-9x=0 ?
The solutions to the equation 18x^2-9x=0 are x= 1/2 ,x=0
Find the zeros of 18x^2-9x=0
The zeros of 18x^2-9x=0 are x= 1/2 ,x=0