What are the solutions to the equation 4x^2-x+6=0 ?

The solutions to the equation 4x^2-x+6=0 are x= 1/8+i(sqrt(95))/8 ,x= 1/8-i(sqrt(95))/8

Find the zeros of 4x^2-x+6=0

The zeros of 4x^2-x+6=0 are x= 1/8+i(sqrt(95))/8 ,x= 1/8-i(sqrt(95))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - x + 6 = 0

x = \frac{1}{8} + i \frac{95}{8}, x = \frac{1}{8} - i \frac{95}{8}

Solution steps

4 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

Simplify

(- 1)^{2} - 4 \cdot 4 \cdot 6 : 95 i

x_{1, 2} = \frac{- ( - 1 ) \pm 95 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 95 i}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 95 i}{2 \cdot 4}

x = \frac{- ( - 1 ) + 95 i}{2 \cdot 4} : \frac{1}{8} + i \frac{95}{8}

x = \frac{- ( - 1 ) - 95 i}{2 \cdot 4} : \frac{1}{8} - i \frac{95}{8}

The solutions to the quadratic equation are:

x = \frac{1}{8} + i \frac{95}{8}, x = \frac{1}{8} - i \frac{95}{8}

- 12 x^{2} + 5 x + 2 = 0

- 8 x^{2} + 3 x - 7 = 0

2 x^{2} - 6 = 4 x

- 12 x + 7 = 5 - 2 x^{2}

s^{2} = 0

What are the solutions to the equation 4x^2-x+6=0 ?
The solutions to the equation 4x^2-x+6=0 are x= 1/8+i(sqrt(95))/8 ,x= 1/8-i(sqrt(95))/8
Find the zeros of 4x^2-x+6=0
The zeros of 4x^2-x+6=0 are x= 1/8+i(sqrt(95))/8 ,x= 1/8-i(sqrt(95))/8