What are the solutions to the equation 2x^2-5x-3=2x-4x^2 ?

The solutions to the equation 2x^2-5x-3=2x-4x^2 are x= 3/2 ,x=-1/3

Find the zeros of 2x^2-5x-3=2x-4x^2

The zeros of 2x^2-5x-3=2x-4x^2 are x= 3/2 ,x=-1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 5 x - 3 = 2 x - 4 x^{2}

x = \frac{3}{2}, x = - \frac{1}{3}

Solution steps

2 x^{2} - 5 x - 3 = 2 x - 4 x^{2}

Move

4 x^{2}

to the left side

6 x^{2} - 5 x - 3 = 2 x

Move

2 x

to the left side

6 x^{2} - 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 3) = 11

x_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 6}

x = \frac{- ( - 7 ) + 11}{2 \cdot 6} : \frac{3}{2}

x = \frac{- ( - 7 ) - 11}{2 \cdot 6} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{3}

2 (2 x + 1)^{2} = (x + 3)^{2} - 10

x^{2} - 2 x = 3

7 x^{2} - 18 = 45

9 x^{2} - 6 x + 7 = 0

- 0.5 x^{2} + 2 x + 1.5 = 0

What are the solutions to the equation 2x^2-5x-3=2x-4x^2 ?
The solutions to the equation 2x^2-5x-3=2x-4x^2 are x= 3/2 ,x=-1/3
Find the zeros of 2x^2-5x-3=2x-4x^2
The zeros of 2x^2-5x-3=2x-4x^2 are x= 3/2 ,x=-1/3