What are the solutions to the equation 9x^2-6x+7=0 ?

The solutions to the equation 9x^2-6x+7=0 are x= 1/3+isqrt(2/3),x= 1/3-isqrt(2/3)

Find the zeros of 9x^2-6x+7=0

The zeros of 9x^2-6x+7=0 are x= 1/3+isqrt(2/3),x= 1/3-isqrt(2/3)

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9 x^{2} - 6 x + 7 = 0

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

Solution steps

9 x^{2} - 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 7}{2 \cdot 9}

Simplify

(- 6)^{2} - 4 \cdot 9 \cdot 7 : 66 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 6 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 6 i}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 6 6 i}{2 \cdot 9}

x = \frac{- ( - 6 ) + 6 6 i}{2 \cdot 9} : \frac{1}{3} + i \frac{2}{3}

x = \frac{- ( - 6 ) - 6 6 i}{2 \cdot 9} : \frac{1}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

- 0.5 x^{2} + 2 x + 1.5 = 0

x^{2} + 5 x + 9 = 0

1 - 2 x + x^{2} = 0

a, a^{2} y^{2} + 3 ab y + 2 b^{2} = 0

c^{2} - 10 c = 0

What are the solutions to the equation 9x^2-6x+7=0 ?
The solutions to the equation 9x^2-6x+7=0 are x= 1/3+isqrt(2/3),x= 1/3-isqrt(2/3)
Find the zeros of 9x^2-6x+7=0
The zeros of 9x^2-6x+7=0 are x= 1/3+isqrt(2/3),x= 1/3-isqrt(2/3)