What are the solutions to the equation factor x^2+7x+12=0 ?

The solutions to the equation factor x^2+7x+12=0 are x=-3,x=-4

Find the zeros of factor x^2+7x+12=0

The zeros of factor x^2+7x+12=0 are x=-3,x=-4

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x^{2} + 7 x + 12 = 0

x = - 3, x = - 4

Solution steps

x^{2} + 7 x + 12 = 0

Factor

x^{2} + 7 x + 12 : (x + 3) (x + 4)

(x + 3) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 4 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = - 3, x = - 4

9 x^{2} - 6 x - 3 = 0

(x - 1)^{2} = - 49

m^{2} + 4 m - 9 = 0

2 x^{2} = 5 x + 2

x^{2} + 8 x + 16 = 7

What are the solutions to the equation factor x^2+7x+12=0 ?
The solutions to the equation factor x^2+7x+12=0 are x=-3,x=-4
Find the zeros of factor x^2+7x+12=0
The zeros of factor x^2+7x+12=0 are x=-3,x=-4