What are the solutions to the equation 4n^2-9n+5=0 ?

The solutions to the equation 4n^2-9n+5=0 are n= 5/4 ,n=1

Find the zeros of 4n^2-9n+5=0

The zeros of 4n^2-9n+5=0 are n= 5/4 ,n=1

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4 n^{2} - 9 n + 5 = 0

n = \frac{5}{4}, n = 1

Solution steps

4 n^{2} - 9 n + 5 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 5 = 1

n_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 4}, n_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 4}

n = \frac{- ( - 9 ) + 1}{2 \cdot 4} : \frac{5}{4}

n = \frac{- ( - 9 ) - 1}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

n = \frac{5}{4}, n = 1

16 x^{2} = 12 x

x (5 x - 4) = 2

x^{2} + 4 x - 5 = 0

16 (1 + 3 x)^{2} + 11 = 36

(x - 3) (x + 3) = 0

What are the solutions to the equation 4n^2-9n+5=0 ?
The solutions to the equation 4n^2-9n+5=0 are n= 5/4 ,n=1
Find the zeros of 4n^2-9n+5=0
The zeros of 4n^2-9n+5=0 are n= 5/4 ,n=1