What are the solutions to the equation factor x^2+4x-5=0 ?

The solutions to the equation factor x^2+4x-5=0 are x=1,x=-5

Find the zeros of factor x^2+4x-5=0

The zeros of factor x^2+4x-5=0 are x=1,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 4 x - 5 = 0

x = 1, x = - 5

Solution steps

x^{2} + 4 x - 5 = 0

Factor

x^{2} + 4 x - 5 : (x - 1) (x + 5)

(x - 1) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

16 (1 + 3 x)^{2} + 11 = 36

(x - 3) (x + 3) = 0

2 x^{2} + 8 x + 16 = 0

x^{2} + 2 x - 1680 = 0

3 x^{2} - 6 x - 15 = 12 x + 12

What are the solutions to the equation factor x^2+4x-5=0 ?
The solutions to the equation factor x^2+4x-5=0 are x=1,x=-5
Find the zeros of factor x^2+4x-5=0
The zeros of factor x^2+4x-5=0 are x=1,x=-5