What are the solutions to the equation 3x^2-6x-15=12x+12 ?

The solutions to the equation 3x^2-6x-15=12x+12 are x=3(1+sqrt(2)),x=3(1-sqrt(2))

Find the zeros of 3x^2-6x-15=12x+12

The zeros of 3x^2-6x-15=12x+12 are x=3(1+sqrt(2)),x=3(1-sqrt(2))

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3 x^{2} - 6 x - 15 = 12 x + 12

x = 3 (1 + 2), x = 3 (1 - 2)

Solution steps

3 x^{2} - 6 x - 15 = 12 x + 12

Move

12

to the left side

3 x^{2} - 6 x - 27 = 12 x

Move

12 x

to the left side

3 x^{2} - 18 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 ( - 27 )}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 (- 27) = 182

x_{1, 2} = \frac{- ( - 18 ) \pm 18 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 18 2}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 18 2}{2 \cdot 3}

x = \frac{- ( - 18 ) + 18 2}{2 \cdot 3} : 3 (1 + 2)

x = \frac{- ( - 18 ) - 18 2}{2 \cdot 3} : 3 (1 - 2)

The solutions to the quadratic equation are:

x = 3 (1 + 2), x = 3 (1 - 2)

x, x^{2} y + 4 y - 8 = 0

(x - 8)^{2} = - 81

12 x^{2} - 88 x + 112 = 0

x, 25 x^{2} + 9 y^{2} + 18 y + 216 = 0

2 x + x^{2} + 1 = 0

What are the solutions to the equation 3x^2-6x-15=12x+12 ?
The solutions to the equation 3x^2-6x-15=12x+12 are x=3(1+sqrt(2)),x=3(1-sqrt(2))
Find the zeros of 3x^2-6x-15=12x+12
The zeros of 3x^2-6x-15=12x+12 are x=3(1+sqrt(2)),x=3(1-sqrt(2))