What are the solutions to the equation 12x^2-88x+112=0 ?

The solutions to the equation 12x^2-88x+112=0 are x=(11+sqrt(37))/3 ,x=(11-sqrt(37))/3

Find the zeros of 12x^2-88x+112=0

The zeros of 12x^2-88x+112=0 are x=(11+sqrt(37))/3 ,x=(11-sqrt(37))/3

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12 x^{2} - 88 x + 112 = 0

x = \frac{11 + 37}{3}, x = \frac{11 - 37}{3}

Solution steps

12 x^{2} - 88 x + 112 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 88 ) \pm ( - 88 ) ^{2} - 4 \cdot 12 \cdot 112}{2 \cdot 12}

(- 88)^{2} - 4 \cdot 12 \cdot 112 = 837

x_{1, 2} = \frac{- ( - 88 ) \pm 8 37}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 88 ) + 8 37}{2 \cdot 12}, x_{2} = \frac{- ( - 88 ) - 8 37}{2 \cdot 12}

x = \frac{- ( - 88 ) + 8 37}{2 \cdot 12} : \frac{11 + 37}{3}

x = \frac{- ( - 88 ) - 8 37}{2 \cdot 12} : \frac{11 - 37}{3}

The solutions to the quadratic equation are:

x = \frac{11 + 37}{3}, x = \frac{11 - 37}{3}

x, 25 x^{2} + 9 y^{2} + 18 y + 216 = 0

2 x + x^{2} + 1 = 0

x, x^{2} y^{2} - 4 x^{2} - 4 y^{2} = 0

2 x^{2} - 4 x - 3 = x

3 y^{2} + 6 y = 0

What are the solutions to the equation 12x^2-88x+112=0 ?
The solutions to the equation 12x^2-88x+112=0 are x=(11+sqrt(37))/3 ,x=(11-sqrt(37))/3
Find the zeros of 12x^2-88x+112=0
The zeros of 12x^2-88x+112=0 are x=(11+sqrt(37))/3 ,x=(11-sqrt(37))/3