What are the solutions to the equation 3y^2+6y=0 ?

The solutions to the equation 3y^2+6y=0 are y=0,y=-2

Find the zeros of 3y^2+6y=0

The zeros of 3y^2+6y=0 are y=0,y=-2

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3 y^{2} + 6 y = 0

y = 0, y = - 2

Solution steps

3 y^{2} + 6 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 0 = 6

y_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 6 + 6}{2 \cdot 3}, y_{2} = \frac{- 6 - 6}{2 \cdot 3}

y = \frac{- 6 + 6}{2 \cdot 3} : 0

y = \frac{- 6 - 6}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

y = 0, y = - 2

s^{2} - 2 s - 3 = 0

- x^{2} + 6 x - 5

x^{2} + 25 = - 10 x

- 2 x^{2} + 4 x - 6 = 0

x, x^{2} + y^{2} + z = 1

What are the solutions to the equation 3y^2+6y=0 ?
The solutions to the equation 3y^2+6y=0 are y=0,y=-2
Find the zeros of 3y^2+6y=0
The zeros of 3y^2+6y=0 are y=0,y=-2