What are the solutions to the equation x^2+25=-10x ?

The solutions to the equation x^2+25=-10x are x=-5

Find the zeros of x^2+25=-10x

The zeros of x^2+25=-10x are x=-5

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x^{2} + 25 = - 10 x

x = - 5

Solution steps

x^{2} + 25 = - 10 x

Move

10 x

to the left side

x^{2} + 25 + 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

x = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

- 2 x^{2} + 4 x - 6 = 0

x, x^{2} + y^{2} + z = 1

9 (5 x + 2)^{2} - 42 = 7

x, f = x^{2} y^{2} - x^{2} y^{3} + 13

3 x^{2} + 4 x - 12 = 0

What are the solutions to the equation x^2+25=-10x ?
The solutions to the equation x^2+25=-10x are x=-5
Find the zeros of x^2+25=-10x
The zeros of x^2+25=-10x are x=-5