What are the solutions to the equation 7m^2+40=43m ?

The solutions to the equation 7m^2+40=43m are m=5,m= 8/7

Find the zeros of 7m^2+40=43m

The zeros of 7m^2+40=43m are m=5,m= 8/7

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7 m^{2} + 40 = 43 m

m = 5, m = \frac{8}{7}

Solution steps

7 m^{2} + 40 = 43 m

Move

43 m

to the left side

7 m^{2} + 40 - 43 m = 0

Write in the standard form

a x^{2} + b x + c = 0

7 m^{2} - 43 m + 40 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 43 ) \pm ( - 43 ) ^{2} - 4 \cdot 7 \cdot 40}{2 \cdot 7}

(- 43)^{2} - 4 \cdot 7 \cdot 40 = 27

m_{1, 2} = \frac{- ( - 43 ) \pm 27}{2 \cdot 7}

Separate the solutions

m_{1} = \frac{- ( - 43 ) + 27}{2 \cdot 7}, m_{2} = \frac{- ( - 43 ) - 27}{2 \cdot 7}

m = \frac{- ( - 43 ) + 27}{2 \cdot 7} : 5

m = \frac{- ( - 43 ) - 27}{2 \cdot 7} : \frac{8}{7}

The solutions to the quadratic equation are:

m = 5, m = \frac{8}{7}

(x - 7)^{2} = 6

(x^{2} - 4 x + 4) = 0

2 x^{2} - 20 x = 0

6 x^{2} + 5 x - 21 = 0

x, (x - 1)^{2} + (y - 3)^{2} = 0

What are the solutions to the equation 7m^2+40=43m ?
The solutions to the equation 7m^2+40=43m are m=5,m= 8/7
Find the zeros of 7m^2+40=43m
The zeros of 7m^2+40=43m are m=5,m= 8/7