What are the solutions to the equation 6x^2+2=32 ?

The solutions to the equation 6x^2+2=32 are x=sqrt(5),x=-sqrt(5)

Find the zeros of 6x^2+2=32

The zeros of 6x^2+2=32 are x=sqrt(5),x=-sqrt(5)

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6 x^{2} + 2 = 32

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

6 x^{2} + 2 = 32

Move

2

to the right side

6 x^{2} = 30

Divide both sides by

6

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

12 x^{2} + 50 = 0

3 x^{2} + x - 15 = 0

p^{2} + 8 p - 3 = 0

- 38 = - 4 c^{2} - 2

- 3 x^{2} + 8 x = 0

What are the solutions to the equation 6x^2+2=32 ?
The solutions to the equation 6x^2+2=32 are x=sqrt(5),x=-sqrt(5)
Find the zeros of 6x^2+2=32
The zeros of 6x^2+2=32 are x=sqrt(5),x=-sqrt(5)