What are the solutions to the equation p^2+8p-3=0 ?

The solutions to the equation p^2+8p-3=0 are p=-4+sqrt(19),p=-4-sqrt(19)

Find the zeros of p^2+8p-3=0

The zeros of p^2+8p-3=0 are p=-4+sqrt(19),p=-4-sqrt(19)

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p^{2} + 8 p - 3 = 0

p = - 4 + 19, p = - 4 - 19

Solution steps

p^{2} + 8 p - 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 3) = 219

p_{1, 2} = \frac{- 8 \pm 2 19}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 8 + 2 19}{2 \cdot 1}, p_{2} = \frac{- 8 - 2 19}{2 \cdot 1}

p = \frac{- 8 + 2 19}{2 \cdot 1} : - 4 + 19

p = \frac{- 8 - 2 19}{2 \cdot 1} : - 4 - 19

The solutions to the quadratic equation are:

p = - 4 + 19, p = - 4 - 19

- 38 = - 4 c^{2} - 2

- 3 x^{2} + 8 x = 0

0 = x^{2} - 4 x - 12

2 x^{2} - 10 x + 18 = 0

2 x^{2} - 8 b x = 2 b^{2}

What are the solutions to the equation p^2+8p-3=0 ?
The solutions to the equation p^2+8p-3=0 are p=-4+sqrt(19),p=-4-sqrt(19)
Find the zeros of p^2+8p-3=0
The zeros of p^2+8p-3=0 are p=-4+sqrt(19),p=-4-sqrt(19)