What are the solutions to the equation 2x^2-8bx=2b^2 ?

The solutions to the equation 2x^2-8bx=2b^2 are x=(2+sqrt(5))b,x=(2-sqrt(5))b

Find the zeros of 2x^2-8bx=2b^2

The zeros of 2x^2-8bx=2b^2 are x=(2+sqrt(5))b,x=(2-sqrt(5))b

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2 x^{2} - 8 b x = 2 b^{2}

x = (2 + 5) b, x = (2 - 5) b

Solution steps

2 x^{2} - 8 b x = 2 b^{2}

Move

2 b^{2}

to the left side

2 x^{2} - 8 b x - 2 b^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 b ) \pm ( - 8 b ) ^{2} - 4 \cdot 2 ( - 2 b ^{2} )}{2 \cdot 2}

Simplify

(- 8 b)^{2} - 4 \cdot 2 (- 2 b^{2}) : 45 b

x_{1, 2} = \frac{- ( - 8 b ) \pm 4 5 b}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 b ) + 4 5 b}{2 \cdot 2}, x_{2} = \frac{- ( - 8 b ) - 4 5 b}{2 \cdot 2}

x = \frac{- ( - 8 b ) + 4 5 b}{2 \cdot 2} : (2 + 5) b

x = \frac{- ( - 8 b ) - 4 5 b}{2 \cdot 2} : (2 - 5) b

The solutions to the quadratic equation are:

x = (2 + 5) b, x = (2 - 5) b

- 9 x^{2} + 18 x = 0

4 r^{2} + 15 r + 7 = - 1

3 x^{2} + 2 (x^{2} - 20) = 16 - 2 x^{2}

r, a = π r^{2}

x^{2} - 6 x - 20 = 0

What are the solutions to the equation 2x^2-8bx=2b^2 ?
The solutions to the equation 2x^2-8bx=2b^2 are x=(2+sqrt(5))b,x=(2-sqrt(5))b
Find the zeros of 2x^2-8bx=2b^2
The zeros of 2x^2-8bx=2b^2 are x=(2+sqrt(5))b,x=(2-sqrt(5))b