What are the solutions to the equation 3x^2+2(x^2-20)=16-2x^2 ?

The solutions to the equation 3x^2+2(x^2-20)=16-2x^2 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of 3x^2+2(x^2-20)=16-2x^2

The zeros of 3x^2+2(x^2-20)=16-2x^2 are x=2sqrt(2),x=-2sqrt(2)

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3 x^{2} + 2 (x^{2} - 20) = 16 - 2 x^{2}

x = 22, x = - 22

Solution steps

3 x^{2} + 2 (x^{2} - 20) = 16 - 2 x^{2}

Expand

3 x^{2} + 2 (x^{2} - 20) : 5 x^{2} - 40

5 x^{2} - 40 = 16 - 2 x^{2}

Move

40

to the right side

5 x^{2} = - 2 x^{2} + 56

Move

2 x^{2}

to the left side

7 x^{2} = 56

Divide both sides by

7

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

r, a = π r^{2}

x^{2} - 6 x - 20 = 0

2 x^{2} + 13 x - 73 = x^{2} - 19

x, z^{3} - 3 x^{2} y + 6 x yz = 0

x^{2} - \frac{1}{5} x - 6

What are the solutions to the equation 3x^2+2(x^2-20)=16-2x^2 ?
The solutions to the equation 3x^2+2(x^2-20)=16-2x^2 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of 3x^2+2(x^2-20)=16-2x^2
The zeros of 3x^2+2(x^2-20)=16-2x^2 are x=2sqrt(2),x=-2sqrt(2)