What are the solutions to the equation x^2-3x+11=9 ?

The solutions to the equation x^2-3x+11=9 are x=2,x=1

Find the zeros of x^2-3x+11=9

The zeros of x^2-3x+11=9 are x=2,x=1

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x^{2} - 3 x + 11 = 9

x = 2, x = 1

Solution steps

x^{2} - 3 x + 11 = 9

Move

9

to the left side

x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

x = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

x = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

x, x^{2} - y^{2} + 4 x + 6 y - 5 = 0

x, 5 x^{2} + 5 y^{2} - 10 x - 10 y = - 25

[(a - 1) x + 2 a - 1] x + 3 a x = 2 a - 3

2 x^{2} + 2 x - 5 = x^{2}

x, z = 1 - x^{2}

What are the solutions to the equation x^2-3x+11=9 ?
The solutions to the equation x^2-3x+11=9 are x=2,x=1
Find the zeros of x^2-3x+11=9
The zeros of x^2-3x+11=9 are x=2,x=1