What are the solutions to the equation 8x^2-22x+15=0 ?

The solutions to the equation 8x^2-22x+15=0 are x= 3/2 ,x= 5/4

Find the zeros of 8x^2-22x+15=0

The zeros of 8x^2-22x+15=0 are x= 3/2 ,x= 5/4

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8 x^{2} - 22 x + 15 = 0

x = \frac{3}{2}, x = \frac{5}{4}

Solution steps

8 x^{2} - 22 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 8 \cdot 15}{2 \cdot 8}

(- 22)^{2} - 4 \cdot 8 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 22 ) \pm 2}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 2}{2 \cdot 8}, x_{2} = \frac{- ( - 22 ) - 2}{2 \cdot 8}

x = \frac{- ( - 22 ) + 2}{2 \cdot 8} : \frac{3}{2}

x = \frac{- ( - 22 ) - 2}{2 \cdot 8} : \frac{5}{4}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{5}{4}

2 x - x^{2} = x^{2}

3 (5 x + 7)^{2} - 18 = 48

0.000006 x^{2} - 0.02 x + 25 = 85 - 0.025 x

3 x^{2} - 4 x - 16 = 0

x, x^{2} + 9 = 0

What are the solutions to the equation 8x^2-22x+15=0 ?
The solutions to the equation 8x^2-22x+15=0 are x= 3/2 ,x= 5/4
Find the zeros of 8x^2-22x+15=0
The zeros of 8x^2-22x+15=0 are x= 3/2 ,x= 5/4