What are the solutions to the equation 12x^2-184x+480=0 ?

The solutions to the equation 12x^2-184x+480=0 are x=12,x= 10/3

Find the zeros of 12x^2-184x+480=0

The zeros of 12x^2-184x+480=0 are x=12,x= 10/3

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12 x^{2} - 184 x + 480 = 0

x = 12, x = \frac{10}{3}

Solution steps

12 x^{2} - 184 x + 480 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 184 ) \pm ( - 184 ) ^{2} - 4 \cdot 12 \cdot 480}{2 \cdot 12}

(- 184)^{2} - 4 \cdot 12 \cdot 480 = 104

x_{1, 2} = \frac{- ( - 184 ) \pm 104}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 184 ) + 104}{2 \cdot 12}, x_{2} = \frac{- ( - 184 ) - 104}{2 \cdot 12}

x = \frac{- ( - 184 ) + 104}{2 \cdot 12} : 12

x = \frac{- ( - 184 ) - 104}{2 \cdot 12} : \frac{10}{3}

The solutions to the quadratic equation are:

x = 12, x = \frac{10}{3}

(5 x + 8)^{2} = 49

x^{2} - 6 x + 5 = 0

4 x^{2} + 24 x - 11 = 0

25 x^{2} - 50 x + 26 = 0

16 x^{2} + 6 x = 0

What are the solutions to the equation 12x^2-184x+480=0 ?
The solutions to the equation 12x^2-184x+480=0 are x=12,x= 10/3
Find the zeros of 12x^2-184x+480=0
The zeros of 12x^2-184x+480=0 are x=12,x= 10/3