What are the solutions to the equation x^2-x=9 ?

The solutions to the equation x^2-x=9 are x=(1+sqrt(37))/2 ,x=(1-sqrt(37))/2

Find the zeros of x^2-x=9

The zeros of x^2-x=9 are x=(1+sqrt(37))/2 ,x=(1-sqrt(37))/2

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x^{2} - x = 9

x = \frac{1 + 37}{2}, x = \frac{1 - 37}{2}

Solution steps

x^{2} - x = 9

Move

9

to the left side

x^{2} - x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 9) = 37

x_{1, 2} = \frac{- ( - 1 ) \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 37}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 37}{2 \cdot 1}

x = \frac{- ( - 1 ) + 37}{2 \cdot 1} : \frac{1 + 37}{2}

x = \frac{- ( - 1 ) - 37}{2 \cdot 1} : \frac{1 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 37}{2}, x = \frac{1 - 37}{2}

3 x^{2} + x + 7 = x^{2} + 10

4 x^{2} = - 1

7 - 7 x = (3 x + 2) (x - 1)

y, M = (y - 3)^{2} + 4 y

\frac{x ^{2} - 5}{2} + \frac{2 x ^{2} - 3 x + 7}{2} = 5

What are the solutions to the equation x^2-x=9 ?
The solutions to the equation x^2-x=9 are x=(1+sqrt(37))/2 ,x=(1-sqrt(37))/2
Find the zeros of x^2-x=9
The zeros of x^2-x=9 are x=(1+sqrt(37))/2 ,x=(1-sqrt(37))/2