What are the solutions to the equation 4x^2=-1 ?

The solutions to the equation 4x^2=-1 are x= 1/2 i,x=-1/2 i

Find the zeros of 4x^2=-1

The zeros of 4x^2=-1 are x= 1/2 i,x=-1/2 i

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4 x^{2} = - 1

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

4 x^{2} = - 1

Divide both sides by

4

x^{2} = - \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{4}, x = - - \frac{1}{4}

- \frac{1}{4} = \frac{1}{2} i

- - \frac{1}{4} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

7 - 7 x = (3 x + 2) (x - 1)

y, M = (y - 3)^{2} + 4 y

\frac{x ^{2} - 5}{2} + \frac{2 x ^{2} - 3 x + 7}{2} = 5

s^{2} - s + 10 = 0

- 2 x^{2} + 28 x - 148 = 0

What are the solutions to the equation 4x^2=-1 ?
The solutions to the equation 4x^2=-1 are x= 1/2 i,x=-1/2 i
Find the zeros of 4x^2=-1
The zeros of 4x^2=-1 are x= 1/2 i,x=-1/2 i