What are the solutions to the equation 3x^2-2x-2=-1 ?

The solutions to the equation 3x^2-2x-2=-1 are x=1,x=-1/3

Find the zeros of 3x^2-2x-2=-1

The zeros of 3x^2-2x-2=-1 are x=1,x=-1/3

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3 x^{2} - 2 x - 2 = - 1

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

3 x^{2} - 2 x - 2 = - 1

Move

1

to the left side

3 x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 1) = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 3}

x = \frac{- ( - 2 ) + 4}{2 \cdot 3} : 1

x = \frac{- ( - 2 ) - 4}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

x^{2} + (n + 1) x + n = 0

5 x^{2} + 9 x + 1

x^{2} - 8 x + 12 = 0

a, y = a^{2}

2 m^{2} - 5 m - 3 = 0

What are the solutions to the equation 3x^2-2x-2=-1 ?
The solutions to the equation 3x^2-2x-2=-1 are x=1,x=-1/3
Find the zeros of 3x^2-2x-2=-1
The zeros of 3x^2-2x-2=-1 are x=1,x=-1/3