What are the solutions to the equation 2m^2-5m-3=0 ?

The solutions to the equation 2m^2-5m-3=0 are m=3,m=-1/2

Find the zeros of 2m^2-5m-3=0

The zeros of 2m^2-5m-3=0 are m=3,m=-1/2

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2 m^{2} - 5 m - 3 = 0

m = 3, m = - \frac{1}{2}

Decimal Notation

m = 3, m = - 0.5

Solution steps

2 m^{2} - 5 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

m_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, m_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

m = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

m = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

m = 3, m = - \frac{1}{2}

y^{2} - 4 y + 1 = 0

x^{2} + 20 x + 109 = 0

x^{2} - 8 x - 105 = 0

4 x^{2} - 4 x + 1 = 0

x, x^{2} - 8 x y + y^{2} = 8

What are the solutions to the equation 2m^2-5m-3=0 ?
The solutions to the equation 2m^2-5m-3=0 are m=3,m=-1/2
Find the zeros of 2m^2-5m-3=0
The zeros of 2m^2-5m-3=0 are m=3,m=-1/2