What are the solutions to the equation x^2-8x-105=0 ?

The solutions to the equation x^2-8x-105=0 are x=15,x=-7

Find the zeros of x^2-8x-105=0

The zeros of x^2-8x-105=0 are x=15,x=-7

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x^{2} - 8 x - 105 = 0

x = 15, x = - 7

Solution steps

x^{2} - 8 x - 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 105 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 105) = 22

x_{1, 2} = \frac{- ( - 8 ) \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 22}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 22}{2 \cdot 1}

x = \frac{- ( - 8 ) + 22}{2 \cdot 1} : 15

x = \frac{- ( - 8 ) - 22}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 15, x = - 7

4 x^{2} - 4 x + 1 = 0

x, x^{2} - 8 x y + y^{2} = 8

x^{2} - \frac{1}{2} x

(3 x - 5)^{2} = 49

x^{2} - 6 x + 10 = 0

What are the solutions to the equation x^2-8x-105=0 ?
The solutions to the equation x^2-8x-105=0 are x=15,x=-7
Find the zeros of x^2-8x-105=0
The zeros of x^2-8x-105=0 are x=15,x=-7