What are the solutions to the equation solvefor x,x^2-8xy+y^2=8 ?

The solutions to the equation solvefor x,x^2-8xy+y^2=8 are x=4y+sqrt(15y^2+8),x=4y-sqrt(15y^2+8)

Find the zeros of solvefor x,x^2-8xy+y^2=8

The zeros of solvefor x,x^2-8xy+y^2=8 are x=4y+sqrt(15y^2+8),x=4y-sqrt(15y^2+8)

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solve for

x, x^{2} - 8 x y + y^{2} = 8

x = 4 y + 15 y^{2} + 8, x = 4 y - 15 y^{2} + 8

Solution steps

x^{2} - 8 x y + y^{2} = 8

Move

8

to the left side

x^{2} - 8 x y + y^{2} - 8 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 8 y x + y^{2} - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 y ) \pm ( - 8 y ) ^{2} - 4 \cdot 1 \cdot ( y ^{2} - 8 )}{2 \cdot 1}

Simplify

(- 8 y)^{2} - 4 \cdot 1 \cdot (y^{2} - 8) : 2 15 y^{2} + 8

x_{1, 2} = \frac{- ( - 8 y ) \pm 2 15 y ^{2} + 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 y ) + 2 15 y ^{2} + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 8 y ) - 2 15 y ^{2} + 8}{2 \cdot 1}

x = \frac{- ( - 8 y ) + 2 15 y ^{2} + 8}{2 \cdot 1} : 4 y + 15 y^{2} + 8

x = \frac{- ( - 8 y ) - 2 15 y ^{2} + 8}{2 \cdot 1} : 4 y - 15 y^{2} + 8

The solutions to the quadratic equation are:

x = 4 y + 15 y^{2} + 8, x = 4 y - 15 y^{2} + 8

x^{2} - \frac{1}{2} x

(3 x - 5)^{2} = 49

x^{2} - 6 x + 10 = 0

2 x^{2} + 14 x + 3 = - 17

2 x^{2} - 14 x + 1 = 0

What are the solutions to the equation solvefor x,x^2-8xy+y^2=8 ?
The solutions to the equation solvefor x,x^2-8xy+y^2=8 are x=4y+sqrt(15y^2+8),x=4y-sqrt(15y^2+8)
Find the zeros of solvefor x,x^2-8xy+y^2=8
The zeros of solvefor x,x^2-8xy+y^2=8 are x=4y+sqrt(15y^2+8),x=4y-sqrt(15y^2+8)