What are the solutions to the equation 4x^2+24x-4=0 ?

The solutions to the equation 4x^2+24x-4=0 are x=-3+sqrt(10),x=-3-sqrt(10)

Find the zeros of 4x^2+24x-4=0

The zeros of 4x^2+24x-4=0 are x=-3+sqrt(10),x=-3-sqrt(10)

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4 x^{2} + 24 x - 4 = 0

x = - 3 + 10, x = - 3 - 10

Solution steps

4 x^{2} + 24 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 ( - 4 )}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 (- 4) = 810

x_{1, 2} = \frac{- 24 \pm 8 10}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 8 10}{2 \cdot 4}, x_{2} = \frac{- 24 - 8 10}{2 \cdot 4}

x = \frac{- 24 + 8 10}{2 \cdot 4} : - 3 + 10

x = \frac{- 24 - 8 10}{2 \cdot 4} : - 3 - 10

The solutions to the quadratic equation are:

x = - 3 + 10, x = - 3 - 10

2 x^{2} - 40 = - 140

2^{2} + 4^{2} = x^{2}

8 x^{2} = 72

x^{2} - 6 x + 9 = 64

x^{2} + 7 x + 15 = 0

What are the solutions to the equation 4x^2+24x-4=0 ?
The solutions to the equation 4x^2+24x-4=0 are x=-3+sqrt(10),x=-3-sqrt(10)
Find the zeros of 4x^2+24x-4=0
The zeros of 4x^2+24x-4=0 are x=-3+sqrt(10),x=-3-sqrt(10)