What are the solutions to the equation x^2+8x+6=0 ?

The solutions to the equation x^2+8x+6=0 are x=-4+sqrt(10),x=-4-sqrt(10)

Find the zeros of x^2+8x+6=0

The zeros of x^2+8x+6=0 are x=-4+sqrt(10),x=-4-sqrt(10)

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x^{2} + 8 x + 6 = 0

x = - 4 + 10, x = - 4 - 10

Solution steps

x^{2} + 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 6 = 210

x_{1, 2} = \frac{- 8 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 10}{2 \cdot 1}

x = \frac{- 8 + 2 10}{2 \cdot 1} : - 4 + 10

x = \frac{- 8 - 2 10}{2 \cdot 1} : - 4 - 10

The solutions to the quadratic equation are:

x = - 4 + 10, x = - 4 - 10

y - 4 < 2

∣ 3 - x ∣ > \frac{2}{3}

\frac{4 !}{3 ! \cdot 1 !}

x^{2} + 9 x - 1 = 0

- 2 x - 2 > 6

What are the solutions to the equation x^2+8x+6=0 ?
The solutions to the equation x^2+8x+6=0 are x=-4+sqrt(10),x=-4-sqrt(10)
Find the zeros of x^2+8x+6=0
The zeros of x^2+8x+6=0 are x=-4+sqrt(10),x=-4-sqrt(10)