What are the solutions to the equation 4x^2+2=5x ?

The solutions to the equation 4x^2+2=5x are x= 5/8+i(sqrt(7))/8 ,x= 5/8-i(sqrt(7))/8

Find the zeros of 4x^2+2=5x

The zeros of 4x^2+2=5x are x= 5/8+i(sqrt(7))/8 ,x= 5/8-i(sqrt(7))/8

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4 x^{2} + 2 = 5 x

x = \frac{5}{8} + i \frac{7}{8}, x = \frac{5}{8} - i \frac{7}{8}

Solution steps

4 x^{2} + 2 = 5 x

Move

5 x

to the left side

4 x^{2} + 2 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

Simplify

(- 5)^{2} - 4 \cdot 4 \cdot 2 : 7 i

x_{1, 2} = \frac{- ( - 5 ) \pm 7 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7 i}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 7 i}{2 \cdot 4}

x = \frac{- ( - 5 ) + 7 i}{2 \cdot 4} : \frac{5}{8} + i \frac{7}{8}

x = \frac{- ( - 5 ) - 7 i}{2 \cdot 4} : \frac{5}{8} - i \frac{7}{8}

The solutions to the quadratic equation are:

x = \frac{5}{8} + i \frac{7}{8}, x = \frac{5}{8} - i \frac{7}{8}

4 x^{2} - 8 x + 9 = 0

- x^{2} + 5 x + 6 = 0

t^{2} - t - 12 = 0

x, x^{2} - 4 x + 1 = 0

x^{2} - 6 x + 1

What are the solutions to the equation 4x^2+2=5x ?
The solutions to the equation 4x^2+2=5x are x= 5/8+i(sqrt(7))/8 ,x= 5/8-i(sqrt(7))/8
Find the zeros of 4x^2+2=5x
The zeros of 4x^2+2=5x are x= 5/8+i(sqrt(7))/8 ,x= 5/8-i(sqrt(7))/8