What are the solutions to the equation 4x^2-8x+9=0 ?

The solutions to the equation 4x^2-8x+9=0 are x=1+i(sqrt(5))/2 ,x=1-i(sqrt(5))/2

Find the zeros of 4x^2-8x+9=0

The zeros of 4x^2-8x+9=0 are x=1+i(sqrt(5))/2 ,x=1-i(sqrt(5))/2

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4 x^{2} - 8 x + 9 = 0

x = 1 + i \frac{5}{2}, x = 1 - i \frac{5}{2}

Solution steps

4 x^{2} - 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

Simplify

(- 8)^{2} - 4 \cdot 4 \cdot 9 : 45 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 5 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 5 i}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 5 i}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 5 i}{2 \cdot 4} : 1 + i \frac{5}{2}

x = \frac{- ( - 8 ) - 4 5 i}{2 \cdot 4} : 1 - i \frac{5}{2}

The solutions to the quadratic equation are:

x = 1 + i \frac{5}{2}, x = 1 - i \frac{5}{2}

- x^{2} + 5 x + 6 = 0

t^{2} - t - 12 = 0

x, x^{2} - 4 x + 1 = 0

x^{2} - 6 x + 1

0 = 3 x^{2} - 12 x - 15

What are the solutions to the equation 4x^2-8x+9=0 ?
The solutions to the equation 4x^2-8x+9=0 are x=1+i(sqrt(5))/2 ,x=1-i(sqrt(5))/2
Find the zeros of 4x^2-8x+9=0
The zeros of 4x^2-8x+9=0 are x=1+i(sqrt(5))/2 ,x=1-i(sqrt(5))/2