What are the solutions to the equation 0=3x^2-12x-15 ?

The solutions to the equation 0=3x^2-12x-15 are x=5,x=-1

Find the zeros of 0=3x^2-12x-15

The zeros of 0=3x^2-12x-15 are x=5,x=-1

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0 = 3 x^{2} - 12 x - 15

x = 5, x = - 1

Solution steps

0 = 3 x^{2} - 12 x - 15

Switch sides

3 x^{2} - 12 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 15) = 18

x_{1, 2} = \frac{- ( - 12 ) \pm 18}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 18}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 18}{2 \cdot 3}

x = \frac{- ( - 12 ) + 18}{2 \cdot 3} : 5

x = \frac{- ( - 12 ) - 18}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

19 x = 7 - 6 x^{2}

4^{2} = 2^{2} + x^{2}

36 x^{2} = - 25

3 x^{2} + 8 x + 6 = 0

- 2 x^{2} + 36 x - 170 = 0

What are the solutions to the equation 0=3x^2-12x-15 ?
The solutions to the equation 0=3x^2-12x-15 are x=5,x=-1
Find the zeros of 0=3x^2-12x-15
The zeros of 0=3x^2-12x-15 are x=5,x=-1