What are the solutions to the equation 4^2=2^2+x^2 ?

The solutions to the equation 4^2=2^2+x^2 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 4^2=2^2+x^2

The zeros of 4^2=2^2+x^2 are x=2sqrt(3),x=-2sqrt(3)

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4^{2} = 2^{2} + x^{2}

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

4^{2} = 2^{2} + x^{2}

Switch sides

2^{2} + x^{2} = 4^{2}

Move

2^{2}

to the right side

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

36 x^{2} = - 25

3 x^{2} + 8 x + 6 = 0

- 2 x^{2} + 36 x - 170 = 0

4 x^{2} - 12 x + 7 = 0

4 x^{2} + 3 = 4 x

What are the solutions to the equation 4^2=2^2+x^2 ?
The solutions to the equation 4^2=2^2+x^2 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 4^2=2^2+x^2
The zeros of 4^2=2^2+x^2 are x=2sqrt(3),x=-2sqrt(3)