What are the solutions to the equation 4x^2+3=4x ?

The solutions to the equation 4x^2+3=4x are x= 1/2+i(sqrt(2))/2 ,x= 1/2-i(sqrt(2))/2

Find the zeros of 4x^2+3=4x

The zeros of 4x^2+3=4x are x= 1/2+i(sqrt(2))/2 ,x= 1/2-i(sqrt(2))/2

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4 x^{2} + 3 = 4 x

x = \frac{1}{2} + i \frac{2}{2}, x = \frac{1}{2} - i \frac{2}{2}

Solution steps

4 x^{2} + 3 = 4 x

Move

4 x

to the left side

4 x^{2} + 3 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 3 : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 4} : \frac{1}{2} + i \frac{2}{2}

x = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 4} : \frac{1}{2} - i \frac{2}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{2}{2}, x = \frac{1}{2} - i \frac{2}{2}

x^{2} + 2 x = - 20

14 x^{2} - 21 x = 0

- 8 x^{2} + 5 = - 4 x

(x - 8)^{2} + (x - 1)^{2} = x^{2}

4 x^{2} - 20 x + 21 = 0

What are the solutions to the equation 4x^2+3=4x ?
The solutions to the equation 4x^2+3=4x are x= 1/2+i(sqrt(2))/2 ,x= 1/2-i(sqrt(2))/2
Find the zeros of 4x^2+3=4x
The zeros of 4x^2+3=4x are x= 1/2+i(sqrt(2))/2 ,x= 1/2-i(sqrt(2))/2