What are the solutions to the equation m^2-8m+15=0 ?

The solutions to the equation m^2-8m+15=0 are m=5,m=3

Find the zeros of m^2-8m+15=0

The zeros of m^2-8m+15=0 are m=5,m=3

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m^{2} - 8 m + 15 = 0

m = 5, m = 3

Solution steps

m^{2} - 8 m + 15 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

m_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, m_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

m = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

m = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

m = 5, m = 3

4 + 8 + 12 + 4 n = 2 n (n + 1)

12 x^{2} + 9 x - 2 = - 17

3 y^{2} - 1 = 0

x^{2} + 24 x = 52

k^{2} + 8 = 8

What are the solutions to the equation m^2-8m+15=0 ?
The solutions to the equation m^2-8m+15=0 are m=5,m=3
Find the zeros of m^2-8m+15=0
The zeros of m^2-8m+15=0 are m=5,m=3