What are the solutions to the equation 6x^2-10x+3=0 ?

The solutions to the equation 6x^2-10x+3=0 are x=(5+sqrt(7))/6 ,x=(5-sqrt(7))/6

Find the zeros of 6x^2-10x+3=0

The zeros of 6x^2-10x+3=0 are x=(5+sqrt(7))/6 ,x=(5-sqrt(7))/6

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6 x^{2} - 10 x + 3 = 0

x = \frac{5 + 7}{6}, x = \frac{5 - 7}{6}

Decimal Notation

x = 1.27429 \dots, x = 0.39237 \dots

Solution steps

6 x^{2} - 10 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

(- 10)^{2} - 4 \cdot 6 \cdot 3 = 27

x_{1, 2} = \frac{- ( - 10 ) \pm 2 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 7}{2 \cdot 6}, x_{2} = \frac{- ( - 10 ) - 2 7}{2 \cdot 6}

x = \frac{- ( - 10 ) + 2 7}{2 \cdot 6} : \frac{5 + 7}{6}

x = \frac{- ( - 10 ) - 2 7}{2 \cdot 6} : \frac{5 - 7}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 7}{6}, x = \frac{5 - 7}{6}

x, 4 x^{2} - 4 x y + 1 - y^{2} = 0

x^{2} - 5 x - 25 = 0

x^{2} - 4 x - 21 = 0

x^{2} + 2 x + 1

x^{2} + 2 x + 4

What are the solutions to the equation 6x^2-10x+3=0 ?
The solutions to the equation 6x^2-10x+3=0 are x=(5+sqrt(7))/6 ,x=(5-sqrt(7))/6
Find the zeros of 6x^2-10x+3=0
The zeros of 6x^2-10x+3=0 are x=(5+sqrt(7))/6 ,x=(5-sqrt(7))/6