What are the solutions to the equation x^2+49=14x ?

The solutions to the equation x^2+49=14x are x=7

Find the zeros of x^2+49=14x

The zeros of x^2+49=14x are x=7

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x^{2} + 49 = 14 x

x = 7

Solution steps

x^{2} + 49 = 14 x

Move

14 x

to the left side

x^{2} + 49 - 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

x = 7

The solution to the quadratic equation is:

x = 7

2 x^{2} - 25 = 0

x^{2} = 1 5^{2} + 8^{2}

x^{2} + 3 x - 8

X^{2} - 3 X + 2 = 0

5 x^{2} - 30 x - 4 = 0

What are the solutions to the equation x^2+49=14x ?
The solutions to the equation x^2+49=14x are x=7
Find the zeros of x^2+49=14x
The zeros of x^2+49=14x are x=7