What are the solutions to the equation X^2-3X+2=0 ?

The solutions to the equation X^2-3X+2=0 are X=2,X=1

Find the zeros of X^2-3X+2=0

The zeros of X^2-3X+2=0 are X=2,X=1

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X^{2} - 3 X + 2 = 0

X = 2, X = 1

Solution steps

X^{2} - 3 X + 2 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

X_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, X_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

X = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

X = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

X = 2, X = 1

5 x^{2} - 30 x - 4 = 0

x^{2} + (18 - x)^{2} = 180

5 x^{2} + 10 x + 3 = 0

2 x^{2} + 12 x + 9 = 0

10 x^{2} - 19 x + 6

What are the solutions to the equation X^2-3X+2=0 ?
The solutions to the equation X^2-3X+2=0 are X=2,X=1
Find the zeros of X^2-3X+2=0
The zeros of X^2-3X+2=0 are X=2,X=1