What are the solutions to the equation x^2+3x-19=0 ?

The solutions to the equation x^2+3x-19=0 are x=(-3+sqrt(85))/2 ,x=(-3-sqrt(85))/2

Find the zeros of x^2+3x-19=0

The zeros of x^2+3x-19=0 are x=(-3+sqrt(85))/2 ,x=(-3-sqrt(85))/2

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x^{2} + 3 x - 19 = 0

x = \frac{- 3 + 85}{2}, x = \frac{- 3 - 85}{2}

Decimal Notation

x = 3.10977 \dots, x = - 6.10977 \dots

Solution steps

x^{2} + 3 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 19) = 85

x_{1, 2} = \frac{- 3 \pm 85}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 85}{2 \cdot 1}, x_{2} = \frac{- 3 - 85}{2 \cdot 1}

x = \frac{- 3 + 85}{2 \cdot 1} : \frac{- 3 + 85}{2}

x = \frac{- 3 - 85}{2 \cdot 1} : \frac{- 3 - 85}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 85}{2}, x = \frac{- 3 - 85}{2}

(5 - 22) x^{2} - (4 + 22) x - 2 = 0

9 x^{2} + 12 x + 5 = 0

x^{2} + 3 x - 16 = 0

x^{2} - 2 a x - 3 a^{2} = 0

4 x^{2} = 32 x - 67

What are the solutions to the equation x^2+3x-19=0 ?
The solutions to the equation x^2+3x-19=0 are x=(-3+sqrt(85))/2 ,x=(-3-sqrt(85))/2
Find the zeros of x^2+3x-19=0
The zeros of x^2+3x-19=0 are x=(-3+sqrt(85))/2 ,x=(-3-sqrt(85))/2