What are the solutions to the equation 5^2=4^2+x^2 ?

The solutions to the equation 5^2=4^2+x^2 are x=3,x=-3

Find the zeros of 5^2=4^2+x^2

The zeros of 5^2=4^2+x^2 are x=3,x=-3

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5^{2} = 4^{2} + x^{2}

x = 3, x = - 3

Solution steps

5^{2} = 4^{2} + x^{2}

Switch sides

4^{2} + x^{2} = 5^{2}

Move

4^{2}

to the right side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

r^{2} + r + 2 = 0

- 6 n^{2} - 8 n = 0

2 x^{2} = - 8

2 x^{2} = 3 - 4 x

(x) (x + 5) = 414

What are the solutions to the equation 5^2=4^2+x^2 ?
The solutions to the equation 5^2=4^2+x^2 are x=3,x=-3
Find the zeros of 5^2=4^2+x^2
The zeros of 5^2=4^2+x^2 are x=3,x=-3