What are the solutions to the equation 2x^2=-8 ?

The solutions to the equation 2x^2=-8 are x=2i,x=-2i

Find the zeros of 2x^2=-8

The zeros of 2x^2=-8 are x=2i,x=-2i

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2 x^{2} = - 8

x = 2 i, x = - 2 i

Solution steps

2 x^{2} = - 8

Divide both sides by

2

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

2 x^{2} = 3 - 4 x

(x) (x + 5) = 414

z^{2} - z - 2 = 0

2 x^{2} + 5 x + 10 = 0

(x - 2)^{2} - 12 = 0

What are the solutions to the equation 2x^2=-8 ?
The solutions to the equation 2x^2=-8 are x=2i,x=-2i
Find the zeros of 2x^2=-8
The zeros of 2x^2=-8 are x=2i,x=-2i