What are the solutions to the equation z^2-z-2=0 ?

The solutions to the equation z^2-z-2=0 are z=2,z=-1

Find the zeros of z^2-z-2=0

The zeros of z^2-z-2=0 are z=2,z=-1

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z^{2} - z - 2 = 0

z = 2, z = - 1

Solution steps

z^{2} - z - 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

z_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, z_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

z = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

z = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

z = 2, z = - 1

2 x^{2} + 5 x + 10 = 0

(x - 2)^{2} - 12 = 0

- 2 x^{2} - 40 = 210

9 x^{2} + 153 x = 0

10 x^{2} - 50 x = 0

What are the solutions to the equation z^2-z-2=0 ?
The solutions to the equation z^2-z-2=0 are z=2,z=-1
Find the zeros of z^2-z-2=0
The zeros of z^2-z-2=0 are z=2,z=-1