What are the solutions to the equation -2x^2-40=210 ?

The solutions to the equation -2x^2-40=210 are x=5sqrt(5)i,x=-5sqrt(5)i

Find the zeros of -2x^2-40=210

The zeros of -2x^2-40=210 are x=5sqrt(5)i,x=-5sqrt(5)i

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- 2 x^{2} - 40 = 210

x = 55 i, x = - 55 i

Solution steps

- 2 x^{2} - 40 = 210

Move

40

to the right side

- 2 x^{2} = 250

Divide both sides by

- 2

x^{2} = - 125

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 125, x = - - 125

- 125 = 55 i

- - 125 = - 55 i

x = 55 i, x = - 55 i

9 x^{2} + 153 x = 0

10 x^{2} - 50 x = 0

4 x^{2} + 8 = - 11 x

x^{2} - 26 x + 25 = 0

5 x^{2} - 168 = - 60 x + 12

What are the solutions to the equation -2x^2-40=210 ?
The solutions to the equation -2x^2-40=210 are x=5sqrt(5)i,x=-5sqrt(5)i
Find the zeros of -2x^2-40=210
The zeros of -2x^2-40=210 are x=5sqrt(5)i,x=-5sqrt(5)i