What are the solutions to the equation 4x^2+8=-11x ?

The solutions to the equation 4x^2+8=-11x are x=-11/8+i(sqrt(7))/8 ,x=-11/8-i(sqrt(7))/8

Find the zeros of 4x^2+8=-11x

The zeros of 4x^2+8=-11x are x=-11/8+i(sqrt(7))/8 ,x=-11/8-i(sqrt(7))/8

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4 x^{2} + 8 = - 11 x

x = - \frac{11}{8} + i \frac{7}{8}, x = - \frac{11}{8} - i \frac{7}{8}

Solution steps

4 x^{2} + 8 = - 11 x

Move

11 x

to the left side

4 x^{2} + 8 + 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 11 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 4 \cdot 8}{2 \cdot 4}

Simplify

1 1^{2} - 4 \cdot 4 \cdot 8 : 7 i

x_{1, 2} = \frac{- 11 \pm 7 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 11 + 7 i}{2 \cdot 4}, x_{2} = \frac{- 11 - 7 i}{2 \cdot 4}

x = \frac{- 11 + 7 i}{2 \cdot 4} : - \frac{11}{8} + i \frac{7}{8}

x = \frac{- 11 - 7 i}{2 \cdot 4} : - \frac{11}{8} - i \frac{7}{8}

The solutions to the quadratic equation are:

x = - \frac{11}{8} + i \frac{7}{8}, x = - \frac{11}{8} - i \frac{7}{8}

x^{2} - 26 x + 25 = 0

5 x^{2} - 168 = - 60 x + 12

7 u^{2} - 7 u + 2 = 0

288 - 6 x^{2} = 0

3 x^{2} + 9 x + 3 = 0

What are the solutions to the equation 4x^2+8=-11x ?
The solutions to the equation 4x^2+8=-11x are x=-11/8+i(sqrt(7))/8 ,x=-11/8-i(sqrt(7))/8
Find the zeros of 4x^2+8=-11x
The zeros of 4x^2+8=-11x are x=-11/8+i(sqrt(7))/8 ,x=-11/8-i(sqrt(7))/8