What are the solutions to the equation 7u^2-7u+2=0 ?

The solutions to the equation 7u^2-7u+2=0 are u= 1/2+i(sqrt(7))/(14),u= 1/2-i(sqrt(7))/(14)

Find the zeros of 7u^2-7u+2=0

The zeros of 7u^2-7u+2=0 are u= 1/2+i(sqrt(7))/(14),u= 1/2-i(sqrt(7))/(14)

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7 u^{2} - 7 u + 2 = 0

u = \frac{1}{2} + i \frac{7}{14}, u = \frac{1}{2} - i \frac{7}{14}

Solution steps

7 u^{2} - 7 u + 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

Simplify

(- 7)^{2} - 4 \cdot 7 \cdot 2 : 7 i

u_{1, 2} = \frac{- ( - 7 ) \pm 7 i}{2 \cdot 7}

Separate the solutions

u_{1} = \frac{- ( - 7 ) + 7 i}{2 \cdot 7}, u_{2} = \frac{- ( - 7 ) - 7 i}{2 \cdot 7}

u = \frac{- ( - 7 ) + 7 i}{2 \cdot 7} : \frac{1}{2} + i \frac{7}{14}

u = \frac{- ( - 7 ) - 7 i}{2 \cdot 7} : \frac{1}{2} - i \frac{7}{14}

The solutions to the quadratic equation are:

u = \frac{1}{2} + i \frac{7}{14}, u = \frac{1}{2} - i \frac{7}{14}

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What are the solutions to the equation 7u^2-7u+2=0 ?
The solutions to the equation 7u^2-7u+2=0 are u= 1/2+i(sqrt(7))/(14),u= 1/2-i(sqrt(7))/(14)
Find the zeros of 7u^2-7u+2=0
The zeros of 7u^2-7u+2=0 are u= 1/2+i(sqrt(7))/(14),u= 1/2-i(sqrt(7))/(14)