What are the solutions to the equation 2x^2-28x=-134 ?

The solutions to the equation 2x^2-28x=-134 are x=7+3sqrt(2)i,x=7-3sqrt(2)i

Find the zeros of 2x^2-28x=-134

The zeros of 2x^2-28x=-134 are x=7+3sqrt(2)i,x=7-3sqrt(2)i

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2 x^{2} - 28 x = - 134

x = 7 + 32 i, x = 7 - 32 i

Solution steps

2 x^{2} - 28 x = - 134

Move

134

to the left side

2 x^{2} - 28 x + 134 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 2 \cdot 134}{2 \cdot 2}

Simplify

(- 28)^{2} - 4 \cdot 2 \cdot 134 : 122 i

x_{1, 2} = \frac{- ( - 28 ) \pm 12 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 12 2 i}{2 \cdot 2}, x_{2} = \frac{- ( - 28 ) - 12 2 i}{2 \cdot 2}

x = \frac{- ( - 28 ) + 12 2 i}{2 \cdot 2} : 7 + 32 i

x = \frac{- ( - 28 ) - 12 2 i}{2 \cdot 2} : 7 - 32 i

The solutions to the quadratic equation are:

x = 7 + 32 i, x = 7 - 32 i

m^{2} + 2 m - 24 = 0

x^{2} + 18 x = 4 x - 49

A, y = A x + A^{2} - B e^{- x}

x, 5 x^{2} + 2 x^{2} y + y^{2} = 8

3 x^{2} + 6 x + 8 = 0

What are the solutions to the equation 2x^2-28x=-134 ?
The solutions to the equation 2x^2-28x=-134 are x=7+3sqrt(2)i,x=7-3sqrt(2)i
Find the zeros of 2x^2-28x=-134
The zeros of 2x^2-28x=-134 are x=7+3sqrt(2)i,x=7-3sqrt(2)i