What are the solutions to the equation -3x^2+6=-1 ?

The solutions to the equation -3x^2+6=-1 are x=sqrt(7/3),x=-sqrt(7/3)

Find the zeros of -3x^2+6=-1

The zeros of -3x^2+6=-1 are x=sqrt(7/3),x=-sqrt(7/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} + 6 = - 1

x = \frac{7}{3}, x = - \frac{7}{3}

Decimal Notation

x = 1.52752 \dots, x = - 1.52752 \dots

Solution steps

- 3 x^{2} + 6 = - 1

Move

6

to the right side

- 3 x^{2} = - 7

Divide both sides by

- 3

x^{2} = \frac{7}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{3}, x = - \frac{7}{3}

4 x^{2} - 10 x - 3

3 (x - 2)^{2} = 7

y^{2} - 9 y + 8 = 0

x, x^{2} + y^{2} - 6 x + 2 y + 12 = 0

(x + 1) (x - 1) = 3

What are the solutions to the equation -3x^2+6=-1 ?
The solutions to the equation -3x^2+6=-1 are x=sqrt(7/3),x=-sqrt(7/3)
Find the zeros of -3x^2+6=-1
The zeros of -3x^2+6=-1 are x=sqrt(7/3),x=-sqrt(7/3)