What are the solutions to the equation x^2+15x+64=20 ?

The solutions to the equation x^2+15x+64=20 are x=-4,x=-11

Find the zeros of x^2+15x+64=20

The zeros of x^2+15x+64=20 are x=-4,x=-11

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x^{2} + 15 x + 64 = 20

x = - 4, x = - 11

Solution steps

x^{2} + 15 x + 64 = 20

Move

20

to the left side

x^{2} + 15 x + 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 44 = 7

x_{1, 2} = \frac{- 15 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 7}{2 \cdot 1}, x_{2} = \frac{- 15 - 7}{2 \cdot 1}

x = \frac{- 15 + 7}{2 \cdot 1} : - 4

x = \frac{- 15 - 7}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 4, x = - 11

a x^{2} + b x - c = 0

s^{2} + 2 s + 10

\frac{x ^{2}}{10} - \frac{x}{5} + 2 = 0

x, x^{2} = - y^{2}

3 = 3 x^{2}

What are the solutions to the equation x^2+15x+64=20 ?
The solutions to the equation x^2+15x+64=20 are x=-4,x=-11
Find the zeros of x^2+15x+64=20
The zeros of x^2+15x+64=20 are x=-4,x=-11